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第12章 三相电路
一、选择题
如图12-1所示为对称三相电路,电源线电压U1=1OOV,线电流I1=2A,负载功率因数λ=cosφ=0.8(感性),功率表接法也如图所示,则此时功率表读数为( )。[上海交通大学2005研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image437.jpg?sign=1739427890-8Qb0xJceOdTWbeY530Qx4rubjFGGvfTF-0-aedcc0e049055ec203fee4405655a7b5)
图12-1
A.208W
B.120W
C.173W
D.0
【答案】A
【解析】选为参考相量,
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image440.jpg?sign=1739427890-3FURvCyVBFGpZHHXnKsO53hNKIgXeB13-0-2832c6075eacafeab8f8331231f07aa3)
二、填空题
1.在如图12-2所示的对称三相正弦交流电路中,所有三只安培表的读数都是10A,如果外加三相对称线电压保持不变,而将AB相负载断开,则电流表A1的读数为_____,电流表A2的读数为_____,电流表A3的读数为_____。[浙江大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image441.jpg?sign=1739427890-Bu2CcUW4rM81Zg8uqTUzQJCnTI6BxilV-0-35bdbad8c1286669ddb7f368fee13d44)
图12-2
【答案】5.77A; 5.77A; 10A
【解析】按一般正弦稳态电路分析方法即可得出结果。
2.图12-3所示三相对称电路中开关S合上时电流表A1的读数是A,则开关S合上时电流表A2的读数是( );A3的读数是( );开关S断开时电流表A1的读数是( );A2的读数是( );A3的读数是( )。[华南理工大学2010研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image443.jpg?sign=1739427890-sP189U3K2e90tz04PxGSu6cPX54SMoXI-0-9487028b877148fa33bc1c8a72bb1ee4)
图12-3
【答案】;
;
;10A;10A
【解析】根据三相电路的对称性,在开关闭合后,三表读数是相同的,即都是;在开关打开之后,
读数不变认为
,
和
的电流表读数变化,线电流变为相电流,为10A。
3.某三角形联接的电力负载,线电压、
及
严重不对称且含有5、7次谐波,该三相负载线电压的零序分量为( )。[华南理工大学2009研]
【答案】
【解析】将不对称的三相线电压分解为三组对称的相量,分别为正序分量、负序分量和零序分量。由于三相线电压中各相对应的正序分量相量和为0、负序分量相量和为0,并且各谐波分量只含有交流分量(即正序、零序分量),无零序分量。则三相线电压的相量和即为三倍的零序分量。即有:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image452.png?sign=1739427890-mfQEoHeifrU21VafFzRfuY8x2KXym47E-0-556fdee4bf3caafd41150d278b9297bf)
4.如图12-4所示对称三相电路中,已知星形连接负载(复)阻抗Z=5+j8.66Ω,若已测得电路无功功率
图12-4
【答案】由Z=5+j8.66Ω可得阻抗角为
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image455.jpg?sign=1739427890-H7JzjJsxawkE7XrgzH2pRz915fG2nlEb-0-0bbbca1644d228eb209f2431181e0a50)
于是有功功率为
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image456.jpg?sign=1739427890-xwvFpNQe9H1gqSRxdXbk5WWuweX7Zfip-0-9ab8c8a1235c2c29d5330ba563d729a6)
三、计算题
1.线电压为
的三相电源上接有两组对称三相负载:一组是三角形联结的电感性负载,每相阻抗
;另一组是星形联结的电阻性负载,每相电阻
,如图12-5所示。试求:(1)各组负载的相电流;(2)电路线电流;(3)三相有功功率。[西南大学2012研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image461.jpg?sign=1739427890-tXndkNO5YrejkR0VHgRov518LIY9Cqp0-0-6e61b2f827d34511c8fcc42122104b19)
图12-5
解:设。
(1)对于星形负载,线电流等于相电流,为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image463.png?sign=1739427890-HhkBveeaFx6Vu41NT2unW9hG5rkhoSmt-0-cfa85120aaddd9dee1792c3796ea1bd1)
星形负载消耗有功为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image464.png?sign=1739427890-CuwxNepSC7xSKscDqJ03TBaqW1IVloL5-0-bd662981ca62b54caeb737987d8de6a9)
对于三角形联结的负载,相电流为线电流的倍。将三角形联结等效为星形联结。得相电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image466.png?sign=1739427890-g47J7qPdrStz0aGt2AglzIPvJBu9J4DB-0-e056b36186abc6562148cbd0a8943740)
线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image467.png?sign=1739427890-LV0mHd9HeyL2E5pzLKyJzWR0AXBSvCB3-0-dc3b92568cf135e6232ee510886e5f19)
(2)电路线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image468.png?sign=1739427890-nXyo64Mg5mtitybMVFObSL7zhfHaPdlv-0-ee0c8b27eaded9794fdf08c36c6d1423)
(3)三角形联结负载消耗有功为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image469.png?sign=1739427890-wkyiu7wrllxOTGwlYlD5rnYUoyoW4Svz-0-0603211142b9d1c8de208cea1a669af6)
则总三相有功功率为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image470.png?sign=1739427890-XDjSglILtqtxySHRnjJtS15SEI1g6zH1-0-bd757d4782e4bb5dea55ec973a37552d)
2.图12-6(a)所示的对称三相电路中,三相电源线电压U1=300V,三相角接负载阻抗(容性)吸收功率P=4500W,三相电源供出的功率PS=7200W,线路阻抗Z1=(3+j3)Ω。试求线电流I1和负载阻抗Z。[天津大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image471.jpg?sign=1739427890-yqlKBtkZkcN6SfmlvdoYuThdzH3BhV84-0-8ac03d3dc12bac2abe4c221525e9290c)
图12-6
解:由已知条件,线路阻抗消耗的平均功率为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image473.png?sign=1739427890-aoSaU7onEMhEW1d3EmxAOWIyiwjVOlKr-0-1375629293458f90a3e175f65531fdae)
则三相电路的线电流为:
将△形负载等效成Y形负载,并取其一相得图(b)所示电路,其中:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image475.jpg?sign=1739427890-A6sj74kHC1gXWkf3KRfMw7R1ZlsebSal-0-0aa90bd82f1ee0b308a7e2d4602a7583)
在图(b)中,相电流等于原电路的线电流。
再由负载消耗功率可知实部为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image477.jpg?sign=1739427890-hFDTZ4UxF9yPE2qT4kaPS7x188wHHegf-0-4687c8707d18841b613610749e2e8f5a)
由题知,负载阻抗为容性,则有:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image478.jpg?sign=1739427890-x5Kz1jCoVG73okSEghYDXO62NVKbt1Qc-0-a69402150b58d56f249a800cbb26ba8c)
解得:XY=9Ω
则△形负载阻抗为:。
3.如图12-7所示对称三相电路中,对称三相电源频率为50Hz,线电压为380V,对称三相负载Z=(18+j24)Ω,对称三相电容负载C=58μF。试求:(1)各线电流;(2)电源发出的复功率。[北京交通大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image480.jpg?sign=1739427890-ZpqFnFQLmYNNWmyDYjzpQPl3eTdQBD8h-0-a7d7881c45e2f5e6c7848f93d0be9e05)
图12-7
解:(1)已知电源线电压为380V,可知相电压(这里设定A相相电压相角为):
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image482.png?sign=1739427890-qawbTeWVM29zVtQuNr38a0ia3JDQW8P8-0-66cefaa021f37cd9a357b84966f742de)
V
V
A
A
A
再由对称性可得、
:
A
A
(2)三相电源的复功率为
V·A
4.图12-8中A、B、C为对称三相电源,已知
图12-8
解:因为A、B、C为对称三相电源,所以
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image495.jpg?sign=1739427890-FL2YNgmIVRMLKGZ5RAYp7OLFzgcwdy4n-0-51a60e1484451e3fe29dfbe28f136878)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image496.jpg?sign=1739427890-Cw6Bn7Ezi71rv280QFj6Pqab0Clt7xH6-0-668756b0af1e847e1098cae7ab772a41)
先求阻抗Z的模值:
由题、
都闭合时,三个电流表读数均为5A,则有:
,解得
=132
。
(1)当开关S1闭合、S2断开时,A1、A2、A3的读数分别为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image502.png?sign=1739427890-ik5Hbiyj3bJgMJ2o3BfPpdH4zMCB9h8W-0-477598f57efff280918f56eb9508ea02)
由对称性知A
不变,即
A
(2)当开关S1断开、S2闭合时,A1、A2、A3的读数分别为:
A
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image507.png?sign=1739427890-pmzDSq9xuQMIKhYk6bI6ZDuIa79NBwYp-0-9502f88415fd0d5697240154a85c0757)
A
5.如图12-9所示电路中,已知对称三相电压源线电压为380V,两组对称负载。第一组负载均为,第二组负载均为
,求:(1)电流表A1、A2、A3的示数;(2)当第二组A相负载发生短路故障后,电流表A1、A2、A3的示数;(3)当第二组A相负载发生断路故障后,电流表A1、A2、A3的示数。[北京交通大学2010研]
图12-9
解:(1)进行变换,得
。令
。
对于电流表A1:,故A1的示数为
A。
对于电流表A3:由,故A3的示数为11A。
对于电流表A2:,又
,
,
,所以
,故A2的示数为
A。
(2)对于电流表A3:,故A3的示数为
A。
对于电流表A2:,故A2的示数为26.9A。
对于电流表A1:设,则
,
,由此可得
,故
。
又,所以:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image533.png?sign=1739427890-Whq5zEnQWXZupjTcVHTkSzUzi0eWfeUg-0-b9882ff97d59c76c9ad902d4053b9e7e)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image535.png?sign=1739427890-1KxALTjA9yRyvpJU2XP05X244cc5gbeD-0-1c5906eb282212f59f13ac174ad8dc83)
因此,A1的示数为65.1A。
(3)对于电流表A1:,故A1的示数为46.5A。
对于电流表A2:,故A2的示数为26.9A。
对于电流表A3:,故A3的示数为9.5A。
6.图12-10所示三相对称电路,已知电压表的读数为,负载阻抗
,线路阻抗
,求图中电流表的读数和线电压UAB。[北京科技大学2011研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image542.jpg?sign=1739427890-Y9A3WkrpbJ7sGxdEiwK6d5ffevzXtR6O-0-d78fd97c77c8e7af5dd50d7ef40fdbef)
图12-10
解:(1)根据对称线电压和对称相电压之间的关系,可得对称相电压
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image543.png?sign=1739427890-j0OO9dlBD1WRu5HxPgdshYGPRX2xs6lg-0-8a300d1067d73cf89f63148f78fbf67d)
则有
A
则电流表的示数为16.67A
(2)则
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image546.png?sign=1739427890-8wg2X4qGozGdfPvzfijXm2svuQnCH3BP-0-6108060182df68a7a6ef5b73fc104fb0)
7.已知如图12-11所示电路中对称三相电源线电压V,阻抗Z1=50+j50Ω,Z2=20Ω,Z3=40+j80Ω,中线电阻R=3Ω。
(1)求图示功率表的读数;
(2)求A相电源uA发出的有功功率和无功功率。[清华大学2005研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image548.png?sign=1739427890-w60CTFpHIhhxdxyIOBS8MzfA3xYV7DLl-0-8b62ae44b173a42764a428a75d4620b2)
图12-11
解:(1)题图所示电路中,阻抗直接并接在A相电源上,对功率表的读数没有影响。求功率表读数电路如图12-12(a)所示,其单相计算电路如图12-12(b)所示。
图(a) 图(b)
图12-12
则可得:
V
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image552.png?sign=1739427890-C6CkXstar2NtnNcuieL4CQTTy7VoLds2-0-9f6d80fe1d5178d2d3caf764864fe46b)
功率表的读数为:。
(2)A相电源发出的有功功率:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image554.png?sign=1739427890-jiyP9gNdidz8OfMETonny55xwesJ4Avw-0-c0b5b47c0a7705e98d16b07d77de37cf)
8.如图12-13所示三相四线制电路中,接有两组对称三相负载和一个单相负载。已知对称三相电源相电压为220V,第一组对称三相负载、
、
的大小。[同济大学2009研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image562.png?sign=1739427890-FzGOy4lqAEPvXu1iLs554tnyduVNXbG8-0-728ed8635276cc75726d8f97aee63b37)
图12-13
解:设A相电压为,则第一组对称三相负载的电流
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image564.png?sign=1739427890-b0A4PiuRKvVqhbbNWIefoDHvBviuGeJ5-0-332c23a3cc43e420695352ea30f09ff6)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image565.png?sign=1739427890-z7gUpH16IcdFTaHz8xz0AnLMcsLGFQVE-0-84d5ab582d9912332086664043f85e43)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image566.png?sign=1739427890-qKpgjtMAH5daQse26taAzYS0vh1WQIP2-0-c8fe849ebd69bead44ba5c50a57b2067)
假设负载为星型连接,则:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image567.png?sign=1739427890-u3LjOC6WgK556wjlElVpW5OZ0XYTlIMV-0-f75927a3ebfe4b0c6a07053670b43fa1)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image568.png?sign=1739427890-slN0T1NooynTMvsqgtd7BkvuaZwJybre-0-39b7d18ad18921c01d0f7fee297e18f6)
故第二组对称三相负载的电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image569.png?sign=1739427890-VjvZp0ZEvKqQfr9aJaMnSIpW3msiy2vn-0-266d28891d60d1219622c77272ff5c71)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image570.png?sign=1739427890-m41cDpNuuUp6301ThyOkwmI9DpgNZqop-0-8965f32742f795a43c2369a4f6bc49bd)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image571.png?sign=1739427890-pIrkPsvIUQTx2uvClDPEuOEXEdEbzyRR-0-ff4cb0f6609a6ebe2d298be928f69497)
单相负载的电流:。
电源端线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image574.png?sign=1739427890-0hrUAfYW3zG874OS98R6X3Zu6HbyOTo1-0-50146980aa901ae63d410269f15f7980)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image575.png?sign=1739427890-Mdc65CkhQwuJMOxPXymYKKU7ptBUmdtP-0-baaae812686feebedae9f4ec0f69c719)
因此:,
,
。